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find the domain of f(x)= (x)/(2cos(x+1))
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For the domain to be true, the denominator cannot be zero. Therefore, what can you plug in for x that makes it zero?
yeah, but i know that cos can't equal -1/2 but what values would i use for radians
i need some help can you help me??
(2n+1)pi/2=x+1 =>x=((2n+1)pi/2)-(1) these are the set of values where ur den =0 hope this hint is enough
\[m<=37 find m<1\]
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