\[2x ^{2} + 11x -21 \] Factor of the polynomial
(x+7)(2x-3)
i factored, or u could use the quadratic formula.....
Could you show me the formula's? I wanna be able to work and understand the problem.
\[x = -b +/- radical b2 - 4ac/2a\]
when you do so much factoring in school, it becomes like multiplication.
whatever
I am confused! xD How do i solve it where do i start?
do u know the quadratic formula?
no, sorry I don't this is all new to me
ok, let me show you
thanks! I appreciate it a lot!
x = -b+/-radicalb2 - 4ac/2a, a,b,c,x2,x, integer.....
the problem is 2x2 + 11x - 21, let a = 2, b = 11, c = -21.....
the plug in the formula, let x = -11 =/- radical121 - 4 times 2 times - 21/2 times 2.....
simplify, eventually it becomes, x = -7, 3/2.....
righting this in factor form means making individual equations!!!!!
easy.....
1. x = -7, (x+7) = 0, 2. x = 3/2, (2x - 3) = 0.....
He doesnt want to solve it......:/
thus, (x+7)(2x-3) = 2x2 + 11x - 21.....
there is no reason to show him quadratic formula. You have to learn both ways of solving for x so you can't avoid factoring by just showing the quadratic formula.
can u leave ryanl, your violating the rules of open study, so contribute, or leave
the quadratic formula is the easiest way for starters since all your doing is plugging in numbers.....
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