Question

Sin-¹(-1/2) without the inverse function

Answer 1

\[Sin^{-1} (\frac{ -1 }{ 2 })\]

Answer 2

\(\large y=Sin^{-1}(\frac{-1}{2}) \rightarrow siny=\frac{-1}{2} \)
now can you determine y?

Answer 3

oh just move sides

Answer 4

remember the domain of arcsin....

Answer 5

oh yes !

Answer 6

y = ???

Answer 7

just remember that because that is a capital Sin^(-1), that means "principle"

Answer 8

how would i find the exact value of that @dpaInc

Answer 9

sorry i haven't learned this sorry

Answer 10

anyone know ? :$

Answer 11

immm really sorry