Question

What is an equation of a line (in point-slope form) that passes through the points (5,1) and (0,2)?

Answer 1

Point-slope form: y − b = m(x − a) for a point (a, b) and slope m
Slope-intercept form: y = mx + b, for slope m and y-intercept b

Answer 2

1. Write y = mx + b
2. Insert the given points into y = mx + b
3. Isolate b in both equations
4. Solve for m, then solve for b.

y = mx + b
2 = 0m + b
1 = 5m + b

2 = b
1 - 5m = b

b = b
1 - 5m = 2
1 - 2 = 5m
-1 = 5m
-1/5 = m

2 = b

Therefore, the slope-intercept form of the line is:
y = -(1/5)x + 2

Answer 3

thankss :))