Question

Algebra 1, radicals help!

Answer 1

It's a correct?

Answer 2

@jim_thompson5910

Answer 3

\[\frac{8q^{2}}{\sqrt{q^{17}}}=\frac{8q^{2}}{\sqrt{q^{14}q^{3}}}=\frac{8q^{2}}{\sqrt{q^{14}}q^{3/2}}=\frac{8\sqrt{q}}{q^7}.\]

Answer 4

Oh geez, I posted the wrong question. @across

Answer 5

There

Answer 6

First cross multiply and then solve for \(x\).

Answer 7

That is,\[2x^2=10x+12.\]You may want to use the quadratic formula.

Answer 8

That is, given\(ax^2+bx+c=0\), then\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.\]