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Mathematics 11 Online
OpenStudy (anonymous):

How would I simplify this?

OpenStudy (anonymous):

OpenStudy (across):

Hint:\[\sqrt{6w^3}\sqrt{12w}=\sqrt{72w^4}.\]

OpenStudy (anonymous):

It was actually supposed to be something like: 6^(3/2)w^(3/2) * 2sqrt3w. Any idea how'd they get that?

OpenStudy (anonymous):

Your answer is the same I got just for the record.

OpenStudy (across):

I just gave you a hint. The "right" answer was obtained by decomposing everything into prime powers, like this:\[\sqrt{6w^3}\sqrt{12w}=\sqrt{6w^3}\sqrt{2^2\cdot3w}=\sqrt{6w^3}2\sqrt{3w}.\]I have no clue how you obtained \((6w)^{3/2}\) for the first term.

OpenStudy (anonymous):

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