[5.01] Part 1: Solve the inequality 3(x + 6) greater than or equal to 4x - 2 and show all of your work. You can use >= to represent the greater than or equal to symbol. Part 2: Use complete sentences to describe the graph of the solution from Part 1.
hmm... well if x equaled 20 then the expressions would be equal.
Which course is this? You can always check lesson 1 in module five and skim through the info there to hep you.
i don't need help, i need to finish this assignment so i can go to homecoming on Saturday. I passed this course but my mom made me re-take it.
okay, so basically your answer is x ≤ 20
i know but i need the equation steps for solving
so I can turn it into complete sentences
3(x + 6) >= 4x - 2 3x+18≥4x−2 −x≥−20 x≤20 so the graph is a solid line going vertically through (20,0) with shading to the right.
Shading to the LEFT!
thank you soooo much
lol, k
what did you do for each line?
3(x + 6) >= 4x - 2 3x+18≥4x−2 : I simplified the expession on the first side of the equal side by multiplying 3 into the other terms.... Then...
−x≥−20 - then I subtracted 4x from both sides of the equation getting a -x on both sides and suntracted 18 from both sides getting -x >= -20 x≤20 after that I divided the entire inequality by -1 which flipped the signs because I dividded the equation by a negative number and the negative sign went away because a negative divided by a negative is a positive.
thank you super duper muchhh
No problem! Sorry It took so long to get the full answer, it took me a sec remember everything from this lesson because i did it some months ago.
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