Question

find zeroes of x^4+36x^2

Answer 1

factor out x-squared and set equal to zero
you should get
x = 0
x = plus or minus 6.

Answer 2

it cant be six because (x+6) (x-6) = x^2 -36 not +36 so i guess its only 0... thanks.

Answer 3

but you're trying to find the zero's. Lol

Answer 4

yeah, its not 6
x^2(x^2+36) = 0
x^2 = 0 , x^2 =- 36
x=0,0 , x=\(\sqrt{-6^2} \implies x=0,0,+6i,-6i \\where \:\: i=\sqrt{-1}\)