Question

Solve for 2x^2-5x+6=0

Answer 1

Factor it out

Answer 2

Not factor able?

Answer 3

then use quadratic formula

Answer 4

\[(-b \pm \sqrt{b^{2}-4ac}) / 2a\]

a = 2
b = -5
c = 6

Answer 5

Workin on it...

Answer 6

should be easy

Answer 7

5+- square root -23/4

Answer 8

\[x = 5/4 + \sqrt{23}\iota\] and \[x = 5/4 - \sqrt{23}\iota\]

Answer 9

Or 5+- SR 23i /4?

Answer 10

It's all over 4, so it becomes 5/4 =) Other than that yes you're completely right

Answer 11

What about the -23 in the square root?

Answer 12

it becomes sqrt(23)(i)
Where\[\iota = \sqrt{-1}\]

Answer 13

You can find an exact value for that in the notation of 5/4 +- 4.796 i

Answer 14

Alrighty then