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How do you group 2x² + 13x + 21 ?
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Given that your quadratic is in the form of ax^2 + bx +c, multiply ac to get 42. Find factors of 42 that add to 13 (the b coefficient). Substitute those coefficients for the middle term, then factor by grouping. In this case, those factors are six and seven.\[2x² + 13x + 21=2x^2+6x+7x+21\]\[=2x(x+3)+7(x+3)=(2x+7)(x+3)\]
Thank you so much!
Do you get it?
Kind of. For every trinomial like this do you rewrite the middle term?
Not every trinomial will be factorable. This method only works if the zeros of the function are rational numbers (fractions).
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Okay
This method is usually only used for problems that have a leading coefficient (a) different than one.
Do math every day.
Okay thanks
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