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What is needed to prove ΔBCA≅ ΔEFD by AAS?
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choices: Angle E= Angle A Angle B= Angle E Segment AB= Segment DE Segment BC= Segment FE
Proving it with AAS means, you need to have two common angles and one common segment (so answer 3 and 4 do not apply). The common segment is already marked in the drawing, as is one of the two common angles. "AAS" means that the common segment must not be the segment between the common angles (as it would give ASA). You can see now what the right answer should be!
Thanks so much, I didn't understand this question regarding the terms AAS.
yw
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yw?
you're welcome
Thanks so much! I'll become a fan to you! :)
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