What is needed to prove ΔBCA≅ ΔEFD by AAS?

Question

falco276 · Answer

attachment

falco276 · Answer

choices:
Angle E= Angle A

Angle B= Angle E

Segment AB= Segment DE

Segment BC= Segment FE

zehanz · Answer

Proving it with AAS means, you need to have two common angles and one common segment (so answer 3 and 4 do not apply). The common segment is already marked in the drawing, as is one of the two common angles. "AAS" means that the common segment must not be the segment between the common angles (as it would give ASA).

You can see now what the right answer should be!

falco276 · Answer

Thanks so much, I didn't understand this question regarding the terms AAS.

zehanz · Answer

yw

falco276 · Answer

yw?

zehanz · Answer

you're welcome

falco276 · Answer

Thanks so much! I'll become a fan to you!
:)