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one muber is 3 times another number less than 12. If the first number is 108, what is the second number?
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let the first numer is x and the 2nd is y, so x = 3(y-12) now if given x=108, it means 108 = 3(y-12) solve for y
*number
ohhh give me a sec to understand
120 is the second number
but how did you know how you put it in a equation?
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i just transleting mathematic statement to algebra languange :)
its principle algebra, u have to know it
thanks
welcome... btw, what's ur answer did u get
120
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108 = 3(y-12) divided by 3 to both sides, gives 108/3 = y-12 36 = y-12 add by 12 to both sides 36+12=y-12+12 48=y hope it helped
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