Question

An object is launched at 25 m/s from a height of 80 m. The equation for the height (h) in terms of time (t) is given by h(t) = -4.9t2 + 25t + 80. What is the object's maximum height?
Answer

Approximately 109 ft

Approximately 110 ft

Approximately 111 ft

Approximately 112 ft

Answer 1

@khem-de-economist

Answer 2

@khem-de-economist

Answer 3

@mathgirl73

Answer 4

it's probably over 9000

Answer 5

IT OVER 9000!!!

Answer 6

max height = c - b^2/4a

Answer 7

111 @petewe

Answer 8

if you plugged that in right, yes

Answer 9

Thanks! (: