Question

1/x^2 + 1/x =6 solve for x

Answer 1

make the left side into 1 equation.

Answer 2

multiply both sides by\(x^2\) and solve the resulting quadratic equation.

Answer 3

\[x^2/ x^2 + x^2/x^2 = 6x^2\]

Answer 4

2x^2 = 6x^2

Answer 5

the denominator of your second term above is wrong

Answer 6

you should get:\[x^2/ x^2 + x^2/x = 6x^2\]

Answer 7

next - simplify each term

Answer 8

but dont they need to have the same denominator to add

Answer 9

what does \(x^2/x^2\) equal?

Answer 10

1

Answer 11

correct - now simplify the next term

Answer 12

1+ x= 6x^2

Answer 13

thats right - now re-arrange this into a standard form, i.e into the form \(ax^2+bx+c=0\) and then solve

Answer 14

so I did quadratic equation and go -1 plus or minus radical 25 all over -12

Answer 15

doesn't look right - can you please show your steps so that I can help spot where you may have made a mistake?

Answer 16

k, u said put it into the standard form so I started from
1 + x = 6x^2
-6x^2 + x+1 = 0
a= -6, b= 1, c= 1
\[-1\pm \sqrt{1^{2}-4(-6)(1) \over 2(-6)}\]

Answer 17

then got -1 plus or minus radical 25 all over -12

Answer 18

oh - sorry - I misread

Answer 19

you are right - and you know what \(\sqrt{25}\) equals?

Answer 20

the formula you used doesn't look quite right, it should be:\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]

Answer 21

the WHOLE thing should be divided by 2a

Answer 22

so you should have got:\[\frac{-1\pm \sqrt{1^{2}-4(-6)(1)}}{2(-6)}\]

Answer 23

o ok so um x = 1/-3 and x = 1/2

Answer 24

perfect!

Answer 25

ya I ment to put all over 2a but I was trying to make it come out nice and pretty in the equation thing but it took lng

Answer 26

although you should write it as:
x=-1/3 or 1/2

Answer 27

you don't usually put the minus sign in the denominator

Answer 28

wow these are so frustrating I was literally about to give up and go home, im in a library trying to study and there are all these other students basically hanging out and talking and there are no available tutors

Answer 29

also note that you should use the word "or" rather than "and" here.

i.e. x = -1/3 or 1/2

instead of x = -1/3 and 1/2

because x canot equal both values at the same time

Answer 30

ok ill do that

Answer 31

thanks a lot you gave me a little hope to keep pushing a little more

Answer 32

great - and keep persevering - you'll get the hang of these very soon I'm sure :)

Answer 33

yw :)