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OpenStudy (icalibear):
just a minute sorry
OpenStudy (sirm3d):
take your time. =)
OpenStudy (icalibear):
OpenStudy (icalibear):
i actually cant figure this out i tried but it ends up wrong
OpenStudy (sirm3d):
reason #2 is based on statement #1. Perpendicular segments (statement #1) form right angles.
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OpenStudy (icalibear):
ok and then thers SAS
OpenStudy (icalibear):
?
OpenStudy (sirm3d):
SAS on reason #3?
OpenStudy (icalibear):
i was thinking for the last one
OpenStudy (sirm3d):
oh. the last part. That's SAS for sure.
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OpenStudy (icalibear):
ok but for 3
OpenStudy (sirm3d):
did you check the given?
OpenStudy (icalibear):
you mean for statement 1 to 2?
OpenStudy (sirm3d):
nope. we're at reason #3
OpenStudy (sirm3d):
we're done with #1 and #2. reason #3 ???
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OpenStudy (icalibear):
thats what im looking for but cant find
OpenStudy (icalibear):
it says the two segements are congruent what property is tht
OpenStudy (sirm3d):
it's not a property. chk the given, maybe it says there.
OpenStudy (icalibear):
SD and HT are perpendicular?
OpenStudy (sirm3d):
the next one.
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OpenStudy (icalibear):
oh i cant see lol yes so it given
OpenStudy (sirm3d):
there are two given statements. (1) \(overline{SD} \bot \overline{HT}\), and (2), the congruent segments SH and ST
OpenStudy (icalibear):
ok the answer to#3 is given
OpenStudy (sirm3d):
now, the reflexive property - that something is equal or congruent to itself. which triangle part is common to the two triangles that you wish to prove congruent?
OpenStudy (icalibear):
segment SD?
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OpenStudy (sirm3d):
right. \(\overline{SD} \cong \overline{SD}\)
OpenStudy (icalibear):
ok so the total answers are
2) perpendicular segments form right angles
3) given
4) SD = SD
5) SAS postulate
??
OpenStudy (sirm3d):
i don't think the angle is "in between" the two sides. |dw:1355612853840:dw|
OpenStudy (icalibear):
yeah its just side side side
OpenStudy (icalibear):
ish
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OpenStudy (icalibear):
SSA?
OpenStudy (icalibear):
is SSA even one
OpenStudy (sirm3d):
but there's the right angle. there's no SSA theorem or postulate, but there's HL triangle theorem
OpenStudy (icalibear):
oh yeah i didnt see that when i said SAS the first time
OpenStudy (sirm3d):
uhm, hypotenuse-leg congruence for right triangles. do you have it in you list of theorems and postulates for triangle congruence?
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OpenStudy (icalibear):
yeah
OpenStudy (sirm3d):
the parts of the right triangle are the hypotenuse (opposite 90 degree angle) and one leg. |dw:1355613144180:dw|
OpenStudy (icalibear):
yeah and the HL
OpenStudy (icalibear):
says that one leg and the hypoteuse are equal
OpenStudy (icalibear):
hypotenuse*
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