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Mathematics 13 Online
OpenStudy (icalibear):

Check my work for this proof? @sirm3d

OpenStudy (icalibear):

just a minute sorry

OpenStudy (sirm3d):

take your time. =)

OpenStudy (icalibear):

OpenStudy (icalibear):

i actually cant figure this out i tried but it ends up wrong

OpenStudy (sirm3d):

reason #2 is based on statement #1. Perpendicular segments (statement #1) form right angles.

OpenStudy (icalibear):

ok and then thers SAS

OpenStudy (icalibear):

?

OpenStudy (sirm3d):

SAS on reason #3?

OpenStudy (icalibear):

i was thinking for the last one

OpenStudy (sirm3d):

oh. the last part. That's SAS for sure.

OpenStudy (icalibear):

ok but for 3

OpenStudy (sirm3d):

did you check the given?

OpenStudy (icalibear):

you mean for statement 1 to 2?

OpenStudy (sirm3d):

nope. we're at reason #3

OpenStudy (sirm3d):

we're done with #1 and #2. reason #3 ???

OpenStudy (icalibear):

thats what im looking for but cant find

OpenStudy (icalibear):

it says the two segements are congruent what property is tht

OpenStudy (sirm3d):

it's not a property. chk the given, maybe it says there.

OpenStudy (icalibear):

SD and HT are perpendicular?

OpenStudy (sirm3d):

the next one.

OpenStudy (icalibear):

oh i cant see lol yes so it given

OpenStudy (sirm3d):

there are two given statements. (1) \(overline{SD} \bot \overline{HT}\), and (2), the congruent segments SH and ST

OpenStudy (icalibear):

ok the answer to#3 is given

OpenStudy (sirm3d):

now, the reflexive property - that something is equal or congruent to itself. which triangle part is common to the two triangles that you wish to prove congruent?

OpenStudy (icalibear):

segment SD?

OpenStudy (sirm3d):

right. \(\overline{SD} \cong \overline{SD}\)

OpenStudy (icalibear):

ok so the total answers are 2) perpendicular segments form right angles 3) given 4) SD = SD 5) SAS postulate ??

OpenStudy (sirm3d):

i don't think the angle is "in between" the two sides. |dw:1355612853840:dw|

OpenStudy (icalibear):

yeah its just side side side

OpenStudy (icalibear):

ish

OpenStudy (icalibear):

SSA?

OpenStudy (icalibear):

is SSA even one

OpenStudy (sirm3d):

but there's the right angle. there's no SSA theorem or postulate, but there's HL triangle theorem

OpenStudy (icalibear):

oh yeah i didnt see that when i said SAS the first time

OpenStudy (sirm3d):

uhm, hypotenuse-leg congruence for right triangles. do you have it in you list of theorems and postulates for triangle congruence?

OpenStudy (icalibear):

yeah

OpenStudy (sirm3d):

the parts of the right triangle are the hypotenuse (opposite 90 degree angle) and one leg. |dw:1355613144180:dw|

OpenStudy (icalibear):

yeah and the HL

OpenStudy (icalibear):

says that one leg and the hypoteuse are equal

OpenStudy (icalibear):

hypotenuse*

OpenStudy (sirm3d):

so HL goes into reason #5

OpenStudy (icalibear):

yep :) thanks so much for helping me!

OpenStudy (sirm3d):

yw. ^^

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