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Mathematics 16 Online
OpenStudy (anonymous):

What is the simplified form of the equation below?

OpenStudy (anonymous):

i look below i no see equation o.o

OpenStudy (anonymous):

hold on!

OpenStudy (anonymous):

HOLDING ON!! D:

OpenStudy (anonymous):

OpenStudy (anonymous):

dividing a fraction by a fraction is the same as multiplying a fraction by the reciprocal of another fraction...like this: \[\huge{{a\over b}\over{c\over d}}~~~~~\implies~~~~~{{a\over b}\times{d\over c}}\]

OpenStudy (anonymous):

so in your case its:\[\huge{{12x\over x^2+6x+9}\over{4x^2\over x^2-9}}~~~~~\implies~~~~~{{12x\over x^2+6x+9}\times{x^2-9\over4x^2}}\] so now just cross multiply

OpenStudy (anonymous):

here are the answers

OpenStudy (anonymous):

so it's the 4th one?

OpenStudy (anonymous):

one sec :)

OpenStudy (anonymous):

\[\large{{12x\over x^2+6x+9}\times{x^2-9\over4x^2}}~~~~~\implies~~~~{{12x\times(x^2-9)}\over{x^2+6x+9\times (4x^2)}}\]sorry i wrote that wrong...this gives you:\[\large{12x^3-108x\over 4x^4+24x^3+36x^2}\]simpllify that

OpenStudy (anonymous):

i simplified it. it's the 2nd one

OpenStudy (anonymous):

yup! :D

OpenStudy (anonymous):

thnx, bro!

OpenStudy (anonymous):

no problem!

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