I'm struggling with the following question, and would greatly appreciate some help: Find, in gradient-intercept form, the equation of the line through: (5,—1), having a gradient of 0. Any ideas?
Do you mean slope? Think about what it means for a line to have 0 slope and see if you can figure out how the line looks like. If you do you should see the equation of the line immediately.
Well, I reckon a slope of 0 would mean that there is no line, but a single point. Now, what that point is, I do not know. Or, am I completely off? Any advice?
There's still a line. slope is rise/run. The only way for this to be 0 is if rise is 0. So, the line is parallel to the x-axis
Could you expound a bit on what you mean by "rise/run", please?
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