use the change of base formula to evaluate log2 74 can someone explain
Are you allowed to use a calculator for this one lilman?
Yes but i have the ti30x and not sure how to use it
Ok so we want to convert the logs to either base 10 or base e, those are the ones that your calculator can handle. Change of Base Formula:\[\huge \log_a b=\frac{\log_{10}b}{\log_{10}a}\]
Using the rule this is what we get, \[\huge \log_2 74=\frac{\log_{10}74}{\log_{10}2}\] Understand how I rewrote that?
yea, but not sure how to use the calculator
Ok calculators can be somewhat confusing.. getting experience with your calculator is important. I would highly recommend getting familiar with the "previous answer" button. You're less prone to make a mistake than if you were to write a ton of parentheses. I'm using a TI-34II It's probably similar, so let's see if we can figure this out.
ok i also have a ti84 and have never figured it out
If you go into higher level math classes, they often won't allow you to use graphing calculators. So it's a good idea to get used to the ole ti30x. :) Hmm so where to get started. Are you using a ti30xs, ti30xa, ti30xb, none of the above? If I find an image of it on google, it might be easier to guide you through the steps.
ti30xlls
This is how I would punch it in, it might seem silly, but I love doing this instead of punching in a ton of brackets. Under the 2nd button, log(2), Enter. It will give you an ugly decimal. Click STO>, Enter. It has now stored that ugly decimal in your calculator. Now click log(74), Enter. Click Divide, Notice that it says\[\large Ans \div\]Ans refers to your previous answer that the calculator gave you. So Ans in this case refers to the log(74) Now press MEMVAR, choose A So you should have something like ANS ÷ A, That will get you your answer. If that's way too confusing, we can do it another way, using brackets and such.
how do i choose a
(, log(74), ), ÷, (, log(2), ), This would be the other way to do it. Maybe it's easier for you. I put commas between each key you need to press.
answer 6.209
Yah looks right! :)
thank you so much have another problem if you have time but ill type in in so you get medals for both
New thread? k sounds good, just type @zepdrix somewhere in the description so i can come find it easier.
ok sounds good
Join our real-time social learning platform and learn together with your friends!