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OpenStudy (anonymous):
How to reduce this into row echelon form?
Answer would be nice as I have done it but the answer in the book is different to my answer.
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OpenStudy (anonymous):
\[\left[\begin{matrix}0 & 1 &3 &2\\ 0 & 0&5&6\\1&5&1&5\end{matrix}\right]\]
OpenStudy (helder_edwin):
1st swap rows 1 and 3
OpenStudy (helder_edwin):
then swap rows 3 and 2
OpenStudy (anonymous):
the answer i get is
\[\left[\begin{matrix}1 & 0&0&-5 \\ 0&1&0&2 &\\0&0&1&0\end{matrix}\right]\]
OpenStudy (helder_edwin):
but this the reduced eschelon form
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OpenStudy (helder_edwin):
never mind. we'll get there
OpenStudy (helder_edwin):
by the way. IF u typed the matrix correctly, the answer your book gives u is wrong
OpenStudy (anonymous):
did you get the same result?
OpenStudy (helder_edwin):
i got
\[ \large \begin{pmatrix}
1 & 0 & 0 & 59/5\\ 0 & 1 & 0 & -8/5\\ 0 & 0 & 1 & 6/5
\end{pmatrix} \]
OpenStudy (anonymous):
thats the answer in the book!!
how did you get this?
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OpenStudy (helder_edwin):
did u do the first two operations i told u?
OpenStudy (helder_edwin):
u should have right now
1 5 1 5
0 1 3 2
0 0 5 6
OpenStudy (anonymous):
i see what i did wrong,
OpenStudy (anonymous):
i first do the reducing then i arrange them in echelon form.
Thank you @helder_edwin
OpenStudy (helder_edwin):
not necessarily. u can perform the operations in the order u see fit.
as long as u don't make mistakes, of course.
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OpenStudy (helder_edwin):
u r welcome
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