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Mathematics 18 Online
OpenStudy (anonymous):

Find all the real and imaginary zeros of the polynomial function: f(x)=6x^3+25x^2+12x-7

OpenStudy (anonymous):

\(x=-1\) works more or less by inspection then you can factor out the \(x+1\) and solve the resulting quadratic. i would do this http://www.wolframalpha.com/input/?i=6x^3%2B25x^2%2B12x-7

OpenStudy (anonymous):

Does this have any imaginary roots?

OpenStudy (anonymous):

did you look at the link?

OpenStudy (anonymous):

I did...so the only roots are -1, -7/2, 1/3?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

it is a polynomial of degree 3, so it can have at most 3 roots. since there are 3 real ones there are no complex ones

OpenStudy (anonymous):

so basically just guess and check and keep using synthetic division?

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