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Find all the real and imaginary zeros of the polynomial function: f(x)=6x^3+25x^2+12x-7
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\(x=-1\) works more or less by inspection then you can factor out the \(x+1\) and solve the resulting quadratic. i would do this http://www.wolframalpha.com/input/?i=6x^3%2B25x^2%2B12x-7
Does this have any imaginary roots?
did you look at the link?
I did...so the only roots are -1, -7/2, 1/3?
yes
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it is a polynomial of degree 3, so it can have at most 3 roots. since there are 3 real ones there are no complex ones
so basically just guess and check and keep using synthetic division?
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