Question

X^3+512=0 real or imaginary solution by factoring

Answer 1

i am going to guess that this is the difference of two cubes

Answer 2

x^3 - 512 = 0
(x - 8)(x^2 + 8x + 64) = 0
x = 8
and
x = (use quadratic roots formula: x = -b +/- √b^2 - 4ac all over 2a)
= -8 +/- √(64 - 256) all over 2
= -8 +/- √-192 all over 2
= -8 +/- 6i√3 all over 2

i means imaginary number because you're taking the square root of a negative number (which is impossible without i)
= -4 +/- 3i√3

Answer 3

No, it was just the problem given and told to find the real or imaginary solutions by factoring

Answer 4

How would you do x^4-3x^2=-2x^2

Answer 5

\[(x - 8)(x^2 + 8x + 64) = 0\]
\(x-8=0\implies x=8\) or
\(x^2+8x+64=0\)
complete the square or use the quadratic formula