Question

Msin(Bt)+Ncos(Bt)=squareroot(M^2+N^2)sin(Bt+C)

Answer 1

Is this how it is supposed to look?

Answer 2

\[M \sin Bt+N \cos Bt=\sqrt{M^2+N^2} \sin (Bt+C)\]

Answer 3

Trying to solutions for the variable t, right?

Answer 4

\[M \sin Bt+N \cos Bt=\sqrt{M^2+N^2}\div \sqrt{M^2+N^2}timesM \sin Bt+N \cos Bt\]

Answer 5

I know I should also use the sum identity for the sine function. But, I'm stuck and have a blank on what to do next.

Answer 6

t = -(1/B) cos^-1