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find the maximum y value on the graph y=f(x) f(y)=-x^2+8x+6
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What math are you in? Algebra?
An equation of this type is of a parabola that opens downward
algebra 2 from what I understand
|dw:1355791776474:dw|
Since this is parabola that opens downward, you're looking for the vertex which is on top. That's the maximum y
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sorry my system went out so since the x^2 and 8x are x does that mean that the high point for y is 6
For parabola ax^2 + bx + c = 0, -b/(2a) gives the x-coordinate of the vertex.
so ot would be -1x^2+8cx+6=0 but then I do not lknow what to do
|dw:1355793024300:dw|
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