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Mathematics 16 Online
OpenStudy (anonymous):

Which conic section does the equation attached describe? A. Circle B. Ellipse C. Parabola D. Hyperbola **my answer: B. ellipse is that right? =)

OpenStudy (anonymous):

zepdrix (zepdrix):

\[\huge \left(\frac{x}{a}\right)^2+\left(\frac{y}{b}\right)^2=1\] See the addition sign between them? Hmm I don't think that quite matches what we're looking for.

OpenStudy (anonymous):

Hyperbola has form \[\frac{(x-h)^2}{a}+\frac{(y-k)^2}{b}=1\]

OpenStudy (anonymous):

ohhh okay so then I'm not too sure :(

zepdrix (zepdrix):

That is the standard form of an ellipse* the one i posted before. Sorry my broswer really screwy :c grr

zepdrix (zepdrix):

no mat :O don't confuse heart. Click the picture for the function, don't look at what I posted.

OpenStudy (anonymous):

ohhh okay hahaa :P wait so I'm confused... what is this then?? :/

zepdrix (zepdrix):

It's a hyperbola... as anhuya said :O

zepdrix (zepdrix):

Oh she posted the wrong sign between them I think.. ugh sec lemme look it up XD

OpenStudy (anonymous):

ohh i see :) it follows that format... :)

OpenStudy (anonymous):

ok :) so what is it then??? :/

OpenStudy (anonymous):

Sorry everyone, mistype Hyperbola form is \[\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1\]

zepdrix (zepdrix):

I find these a little confusing because of all the extra numbers they throw at you. The -1 in x -1 just represents a horizontal shift to the right 1 unit. It doesn't affect the SHAPE of the graph at all. So I would recommend ignoring data like that. It might help you to see what's going on. The function essentially looks something like this,\[\huge \left(\frac{x}{a}\right)^2-\left(\frac{y}{b}\right)^2=1\]

OpenStudy (anonymous):

okay, so i need to find the one that follows that format?

zepdrix (zepdrix):

Yah c:

zepdrix (zepdrix):

It might appear in your book as anhuya posted it.

OpenStudy (anonymous):

okay, so this is a hyperbola? :/

OpenStudy (anonymous):

like @anhhuyalex said?

OpenStudy (anonymous):

or wrote above?

zepdrix (zepdrix):

yah c: hyperbola.

OpenStudy (anonymous):

okay!!! thank youu :)

OpenStudy (anonymous):

its hyperbola i din't look ur post

OpenStudy (anonymous):

haha okay thanks :)

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