Question

Could some please help me with my problem?



Using the triangles below, what is the range of possible values for x?

Answer 1

It looks like you can set up an inequality here using 90 degrees compared to that angle.

Answer 2

Oh so how would I set up an inequality using 90 degrees? 90 <x< 4x - 8 ?

Answer 3

@Kainui ?

Answer 4

I think you've put your inequality signs backwards and that middle "x" term is unnecessary.

Answer 5

Isn't 90 degrees larger than the angle that's 4x-8? Then you also know that 4x-8 is larger than 0. Then you can manipulate it with algebra to solve for x. I'll help walk you through it, I'm purposefully trying to get you to solve it on your own with little help because I know you can do it. =D

Answer 6

Thanks
...
90>4x - 8
98 > 4x
?
90> 2(4x -8)
90> 8x - 16
I'm super confused on this?

Answer 7

90>4x-8>0
That's where you should start, and your first step is correct in solving for x.

98>4x>8

Now you only have to do one more step from here.

Answer 8

98> 4x>8
98> x = 2

Answer 9

Nope, almost though. You don't turn the greater than sign to an equals sign, and you divide both sides by 4 not just the right one.

Here's an example to show you that this works.

6>2x>2

divide everything by 2

3>x>1

Or let's look at another example

5>x+3>3

do the same thing to all sides to solve for x, in this case, subtract 3

2>x>0

Make sense? It's a lot like what you do with an equals sign.

Answer 10

so .....
98> 4x>8
24.5>x>2

Answer 11

?

Answer 12

Exactly.

Answer 13

Oh wow thank you so much @Kainui

Answer 14

No problem, glad I could help! =D