Question

Through(-5,1) slope (- 6 over 5)

Answer 1

@mathstudent55

Answer 2

y = mx + b, m = slope = -6/5, x = -5, y = 1
Insert all known values above into above equation:
1 = (-6/5)(-5) + b
Solve for b
1= 6 + b
b = -5
Now that you know m and b, insert them back into slope-intercept equation:
y = (-6/5)x - 5

Answer 3

thank you again i may need some other help in a bit

Answer 4

find the slope of a line perpendicular to each given line ...... y = - 4 over 5 x -1

Answer 5

I'll do this one, but then I need to go.
The slope of perpendicular lines are negative reciprocals. Reciprocals are numbers that multiply to 1. Negative reciprocals are numbers that multiply to -1. This explanation may seem long, but the concept is simple to do.
How do you find the reciprocal of a number?
First, write the number as a fraction.
Then, flip the fraction. That's the reciprocal.
Since for the slope of a perpendicular line you need a negative reciprocal, then first write the slope of the given line as a fraction, then flip the fraction and change the sign. There's your negative reciprocal.
For example, a line has slope 5/6. What isd the slope of a perpendicular?
Flip 5/6 and get 6/5. Then change the sign. Since 6/5 is positive, make it negative. Answer: -6/5
Another example:
A line has slope -2. What is the slope of a perpendicular to this line? First write -2 as a fraction: -2/1. Now flip it: -1/2. Now change the sign. Answer: 1/2

Answer 6

Now let's look at your problem.
Find the slope of a line perpendicular to each given line ...... y = - 4 over 5 x -1
y = (-4/5)x - 1
This line is already in slope-intercept form, y = mx + b. The slope is m, so in this case the slope is -(4/5)
To get the slope of a perpendicular, you need the negative reciprocal of -(4/5). So flip it and change the sign: 5/4