Question

Show that (√6 + √2)/(√6 - √2) = 2+√3

Answer 1

(√6 + √2)/(√6 - √2) = 2+√3

( x+ 1 ) ( x - 1 ) difference of squares

(√6 + √2)/(√6 - √2) = 2+√3
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\do you see that this follows difference of squares format?

Answer 2

yes I do see it as that .. but remember itz divided by right ..

Answer 3

\[\frac{\sqrt{6}+\sqrt{2}}{\sqrt{6}-\sqrt{2}}\times \frac{\sqrt{6}+\sqrt{2}}{\sqrt{6}+\sqrt{2}}\] is probably a good start

Answer 4

yes it is because it is a surd .. but when i work it out i end up with two root threes and itz suppose to be one so im a bit confused .

Answer 5

same thing what satellite did.