Question

(2x^4y)/(6xy^2)
Help!

Answer 1

\[x ^{2}\times x ^{3 } = x ^{2+3}\]
if being divide
\[\frac{ x ^{3} }{ x ^{2} } = x ^{3-2}\]

Answer 2

\[\frac{ 2x ^{4}y }{ 6xy ^{2}}\]
now apply the same technique on your question.

Answer 3

I know how to do that for ex. if the question was \[6x^4y^2\div2xy \] it would be 3x^3y
I just get confused when I have numbers and exponents on the top that are greater than the ones on the bottom.

Answer 4

**less than the ones on the bottom

Answer 5

doesn't matter .. if you have a power in numerator less then denominator you can write it as
y^2/y^3
\[\frac{ 1 }{ y } \] OR
\[ y ^{-1}\]

Answer 6

both of these are same things.. so u can write them either way both are correct.

Answer 7

Would \[\frac{ 1x^3 }{ 3y } \] Would that be correct?

Answer 8

yes..