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How do I get it to where sin is on one side alone?? I need sin^2x alone.. Thanks!
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will you please elaborate your query ?
That's my equation. In order to find what \[\sin^2x\] equals, I need to get it alone. But I just don't know how to get it out of the denominator.
Can I just cross multiply?
ya why not..cross multiply simply..that should do the trick,..
Okay, thanks :)
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You can also just invert the fractions. so 4 becomes 1/4, and 1/sin^2x becomes sin^2x.
Oh, okay. That's a lot easier. Thanks!! :)
No prob :)
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