Question

I've been stuck on these for a while.... Posting pictures

Answer 1

@UnkleRhaukus

Answer 2

@AccessDenied

Answer 3

Ok you might want to draw them as lines, that helps me anyway. I'll do 45 c and 46 b for you.


1. Find the longest chain.
2. Look for unsaturations in this chain.
3. Look for substituents on this chain.

45c:
The longest chain is 4, which means "but". There are no unsaturations, which means "ane". There is a methyl group. Start counting from the side closer to the methyl group. This makes it on the 2nd carbon. So the name is 2-methylbutane.

46b:
The longest chain is 5, which means "pent". There is an unsaturation: a double bond, which means "ene". So start counting from the side closer to the unsaturation (if there were a substituent, the unsaturation takes priority). This makes the double bond at the second carbon. There are no substituents. So the name is pent-2-ene.

Answer 4

I recommend the khan academy videos if you're having trouble with this.

http://www.khanacademy.org/science/organic-chemistry/v/more-organic-chemistry-naming-examples-1