Can you see if this is right?
For how many x values will the tanget lines to y=4sinx and y=x^2/2 be parallel?
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OpenStudy (anonymous):
y'=4cosx
4cosx=1/2
cosx=1/8
OpenStudy (anonymous):
or is it 4cosx=x^2/2
OpenStudy (anonymous):
4cosx = x is the answer!
OpenStudy (anonymous):
for some reason the answer is supposed to be 3...
OpenStudy (kainui):
Ahh I see. Take the derivatives and graph them and see where they intersect. They intersect 3 points which means that the slopes of the graphs at that x-value is exactly the same.
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OpenStudy (anonymous):
do i take the derivative of the second equation too?
OpenStudy (anonymous):
or just the first one?
OpenStudy (anonymous):
i just derived them and equal them. theie ramp should be parallel!
OpenStudy (anonymous):
so would it be 4cosx=x^2/2
or 4cosx=x?
OpenStudy (anonymous):
the second derive is X. \[^{2}=2x \rightarrow 2x.1/2=X\]
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OpenStudy (anonymous):
can you explain that?
OpenStudy (anonymous):
clear?!
OpenStudy (anonymous):
whats your equation supposed to be?
OpenStudy (anonymous):
2x.1/2=x ??
OpenStudy (anonymous):
yea
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OpenStudy (anonymous):
Kay thank you
OpenStudy (anonymous):
ur pleasure;) if u need more explains, i can help:)