i want to graph 3csc2x but I dont know how!! can someone help me with steps!??
do u knw the graph of cosec x?
One way might be to try rewriting 3csc(2x) as 3/sin(2x). Then from here, mark on your graph where one period should end and where the amplitude should be. Since it's 1/sin it will be "upside down" Look at this picture to give yourself some help along the way so that next time you can see. http://www.wolframalpha.com/input/?i=%203csc(2x)&t=crmtb01 The main points to hit when graphing any trig function are what it looks like at 0, T/4, T/2, 3T/2, and T, since it repeats after that and you can kind of "guess" by filling in the points between where the curve should look like.
i know that cscx = 1/sinx
so if i put that function... 3/sin(2x)?
i can help with an alternate solution ..but for that you need to answer my queries
the graph of csc ..yes i do know what it is!
Find the amplitude and period.
well thats great...now what you need to understand is that the graph of cosec 2x will be same as cosec x only difference is that we have to minimize the graph to t=pi
let me show u how i do that for sin 2x
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