Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

i want to graph 3csc2x but I dont know how!! can someone help me with steps!??

OpenStudy (aravindg):

do u knw the graph of cosec x?

OpenStudy (kainui):

One way might be to try rewriting 3csc(2x) as 3/sin(2x). Then from here, mark on your graph where one period should end and where the amplitude should be. Since it's 1/sin it will be "upside down" Look at this picture to give yourself some help along the way so that next time you can see. http://www.wolframalpha.com/input/?i=%203csc(2x)&t=crmtb01 The main points to hit when graphing any trig function are what it looks like at 0, T/4, T/2, 3T/2, and T, since it repeats after that and you can kind of "guess" by filling in the points between where the curve should look like.

OpenStudy (anonymous):

i know that cscx = 1/sinx

OpenStudy (anonymous):

so if i put that function... 3/sin(2x)?

OpenStudy (aravindg):

i can help with an alternate solution ..but for that you need to answer my queries

OpenStudy (anonymous):

the graph of csc ..yes i do know what it is!

OpenStudy (kainui):

Find the amplitude and period.

OpenStudy (aravindg):

well thats great...now what you need to understand is that the graph of cosec 2x will be same as cosec x only difference is that we have to minimize the graph to t=pi

OpenStudy (aravindg):

let me show u how i do that for sin 2x

OpenStudy (aravindg):

|dw:1355991064248:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!