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Biology 16 Online
OpenStudy (anonymous):

Help please? Enzymes?

OpenStudy (anonymous):

Enzyme A is an enzyme that catalyzes the breakdown of the Substance B. Which of the following explains why Enzyme A cannot be used to catalyze the breakdown of substance C?

OpenStudy (anonymous):

Binding with an alternate substance would inhibit the reaction of the enzyme. Its shape determines the substance that it can react with. It would require a level of activation energy that is too high. Reacting with another substance would halt the production of the enzyme and raise the overall activation energy.

OpenStudy (anonymous):

?

OpenStudy (frostbite):

*sigh* You know what a enzyme is?

OpenStudy (anonymous):

yeah

OpenStudy (frostbite):

Okay... Tell me about the specific properties of the enzyme. (the answer is in the specific properties)

OpenStudy (anonymous):

D?

OpenStudy (frostbite):

We say that a enzyme is substrate specific (functional specific) So depending on how the substrate C is diffrent from B it can not be done... So the answer is "Its shape determines the substance that it can react with."

OpenStudy (frostbite):

Source: Me (biochemistry student)

OpenStudy (anonymous):

Thank you!

OpenStudy (frostbite):

But it is a bit strange question... for an example you can have two molecules diffrence from each other but the affinity is not the same. If this is the situation the both substances can react with the enzyme, however the rate of the reacton is not the same. That can esay be seen from this equation: \[V _{0}=\frac{ V _{\max} }{ 1+\frac{ K _{M} }{ [S] } }\]

OpenStudy (frostbite):

That equation is known as the MM-equation / Michaelis-Menten-model.

OpenStudy (anonymous):

Thanks, I understand now. :) Most of the questions on my worksheet are worded a bit oddly.

OpenStudy (frostbite):

No problem. If other questions like this just let me know.

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