Solve algebraically: x-3y-3z=0 2x+5y-5z=1 -x+5y-6z=-9
hey, this ques? :P
Yes
ok, this can be done by substitution method, Find value of any variable, for ex: x from given 1st equation in terms of y and z (call this 'ur' 1st eqn) then put in given 2nd equation and find value of y in terms of z.(call it 'ur' 2nd eqn) Then put value of y in 'ur 1st' equation, you will get value of x also in terms of z then put the values of both y and x in given 3rd eqn, solve it! you will get value of z Put in the respective 'ur' 2 equations and u will get value of x and y also :D
See now here the solution becomes quite lengthy, right? So you can use the alternate method! Wanna learn? :)
Yes!
ok
got my msg?
Yeah
I don't need this question answered anymore. My teacher excluded it from the lesson. thanks though :)
the alternate method basically is just like combination.
wanna learn or not? :P
btw ans is, x=3, y=0, z=1
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