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Mathematics 8 Online
OpenStudy (anonymous):

the length of a rectangle is 10 inches more than 1.5 its width. if the perimeter of the rectangle is 44, what are the dimensions

OpenStudy (anonymous):

Supposed to say 1/5

OpenStudy (anonymous):

P = 44 = 2w + 2[(1/5)w + 10] You now have one equation in one variable that you can solve. The factor of 2 in front of the two terms is from 2w + 2L because its a rectangle.

OpenStudy (anonymous):

(12/5)w = 24 -> w = 10

OpenStudy (anonymous):

@mweisberg the problem is finished now.

OpenStudy (anonymous):

All good now?

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