Question

the length of a rectangle is 10 inches more than 1.5 its width. if the perimeter of the rectangle is 44, what are the dimensions

Answer 1

Supposed to say 1/5

Answer 2

P = 44 = 2w + 2[(1/5)w + 10]

You now have one equation in one variable that you can solve. The factor of 2 in front of the two terms is from 2w + 2L because its a rectangle.

Answer 3

(12/5)w = 24 -> w = 10

Answer 4

@mweisberg the problem is finished now.

Answer 5

All good now?