Question

Solve the exponential equation
9^2x = 27

Answer 1

9 = 3^2

9^2x = 3^4x

27 = 3^3

Compare

4x = 3

x = 3/4

Answer 2

We have\[9^{2x}=27\]
\[(3^{2})^{2x}=3^{3}\]
\[3^{4x} = 3^{3}\]
so 4x = 3

Answer 3

Can I get an explanation on how you did that?

Answer 4

9 is nothing but 3^2 and 27 is 3^3
so we need to make the base common to make it possible to solve for 'x'....
so...............
3^2(2x) = 3^3
therefore 3^4x = 3^3
since the base is the same, the exponents are equal;( since it is an equation and the left hand side is equal to the right hand side).
so, 4x = 3
hence x = 3/4

Answer 5

did u understand my explanation @Jadelynn ? because if u didnt i can explain again

Answer 6

Yes I did. Thank you

Answer 7

Good explanation, @ShikhaDessai

Answer 8

thank you so much!!!

Answer 9

how do you solve the equation 9^2x = 27

Answer 10

using exponential and logarithmic form

Answer 11

@66 maybe post a new question... this one is four months old.

Answer 12

not mine please help if posible

Answer 13

"how do you solve the equation 9^2x = 27"

Or... just read above... your question is already answered above and explained twice...

Answer 14

kk thx a lot

Answer 15

If you need to do it with logarithms, then take logarithms of both sides of 9^2x = 27

Answer 16

how do you do that and its not solved above

Answer 17

can you please help if not then i will google search it , but thanks for your help anyway

Answer 18

??????????????????????????

Answer 19

does anyone know how to solve for the equation 9^2x = 27