You guys will argue over anything. 6÷2(1+2)
already argued over this...and consensus was its 6
sorry 9
We are conversing, aren't we?
It's 9. Next question.
I disagree that it's 9.
Why is it 9 and not 13?
Abb0t, demonstrate your calculations.
P E MD AS 6/2(1+2) 6/2(3) Left to right! MD 6/2=3 3(3)=9 My answer is 9
\[\int\limits_{0}^{L/2}dx_1\int\limits_{0}^{L/2} dx_2|\Psi(x_1, x_2)|^2=\int\limits_{0}^{L/2}dx_1\int\limits_{0}^{L/2}dx_2|\Psi_1^2(x_1)\Psi_2^2(x_2)-\Psi_1(x_1)\Psi_1(x_2)\Psi_2(x_1)|\] Which is \[I_1I_2-I_{12}^2\] Where: \[I_1= \int\limits \Psi_1^2(x)dx= \frac{ 1 }{ 2 } \] and \[I_2= \int\limits \Psi_2^2(x)dx=\frac{ 1 }{ 2 } \] and \[I_{1,2} = \int\limits\limits \Psi_1(x) \Psi_2(x)dx = \pm \frac{ \sqrt{51} }{ 2 }i\] Resulting in 13
Demonstrate your calculation @Compassionate
WOAHH....@abb0t what did you bring in?!! I dont see any squiggles in the main problem!!
pemdas is correct. It should be 9 though :) happy holidays all!
I said it was 9!! Happy that I am right!
Ouch I have a headache... What in the world did you type @abb0t It's like in swahili...
Hahahah I couldn't even understand it.
Looks like stuff from Quantum Mechanics, at least that's the only time I ever saw Psi used like that... Although I don't know much about the subject. :p
Particle in a box :)
eh?
it could also be 1, if you distributed.... :)
Haha. My initial thought was 1, but I 4got about PEMDAS.
\[6÷2(1+2)=3(3)=9\]
@Hero so you are saying you hate math
9
can we really directly assume that its not 2*3 together there? with that, it comes to be 1 :/
i see..didnt know that..hmm..
^ Lol. Didn't click.
Nothing risque or of that sort ;)
It seems you've convinced me to click your nonsensical link.
holy crap look at all these people viewing this...
they both suck
Indeed. http://www.reactiongifs.com/wp-content/uploads/2012/08/well_done_sir.gif
We are conversing, aren't me?
Yes, yes me am.
The answer is 6. Deal with it.
http://25.media.tumblr.com/2d2705971bf7e09042b01801324eef91/tumblr_mfngbsaGs61rgw59ro1_500.gif Its 9
http://4.bp.blogspot.com/-gGxLlnvQbaw/Tv4JvavQdKI/AAAAAAAAA6c/WshTxyn1dJk/s1600/yes_it_is.jpg
My gifs went to sleep. In other words, too lazy to argue.
In others words, you lose.
9
6
Wolfram is obviously wrong.
@Compassionate i'm having trouble understanding what your trying to achieve by being difficult...were you not loved as a child?
^ Oh yeah. http://media.tumblr.com/9a8c5f5eb3110712142fc0956932008b/tumblr_inline_mfgxjv2UhX1rnwch7.gif
So...to conclude: if a person asks this or writes this down, he has to formulate it better! Use another set of brackets.
I was molested by a reindeer. Don't bring up the bad memories. It's 6.
I kinda didn't like compassionate, but now I actually don't mind him cause he's actually fairly mediocre at trollin'.
Prove that it's 9. http://i3.kym-cdn.com/photos/images/original/000/166/212/DO%20IT%20owletGOT%202.jpg
Yeah, trolling isn't really trolling when it's transparent
Unless I'm also trollin'.
ITT: Trolls trolling trolls who were originally meant to be trolled by trolls.
d'ah!
Zzzzz
Cary on my wayward son.
http://media.tumblr.com/aead2aa43a748ed4d1ed60f9eb7549a6/tumblr_inline_mfjeupVtMI1r9naon.gif I hope there are no children here.
the "sqiggles" are integrals :) i don't even know what he did... some math magic wala!
http://media.tumblr.com/80b547f875515df74cc4992744807e86/tumblr_inline_mfes61dkhj1rxa4z0.gif
Rage.
@karatechopper the "sqiggles" are integrals :) i don't even know what he did... some math magic wala!
Ohyes
I know they are integrals. but i like to call them squiggles
haha oh sowwy but i really don't know what he did. i would say.... BS!!!!
We can call them squishies.
squiggles!!!
\[\int\limits_{\int\limits_{\int\limits_{\int\limits_{}^{}}^{\int\limits_{}^{}}}^{\int\limits_{\int\limits_{}^{}}^{\int\limits_{}^{}}}}^{\int\limits_{\int\limits_{\int\limits_{}^{}}^{\int\limits_{}^{}}}^{\int\limits_{\int\limits_{}^{}}^{\int\limits_{}^{}}}} \]
all this is is a poorly defined statement, but the convention is to go from left to right with MD
Refer to the following with regard to operator precedence: http://en.cppreference.com/w/cpp/language/operator_precedence 6÷2(1+2) -> (6÷2)*(1+2) -> (3)*(1+2) ->3+6 -> 9
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