find the domain of the rational function f(y)= y+3/y^2-3y type the answer in interval notation
domain is 0 and 3
@KeKiu, how do you write in interval notation
do you know how to find the domain? tho?
no can you show me
so your equation is (y+3)/(y^2-3y) is that correct?
whenever you ask to find domain you are being ask to find the maxium of value X so to find domain, is to find the bottom part of the equation, which is y^2-3y
yes but no parenthesis
ok I got that
so you would look at the bottom as a equation and set to 0, which is y^2-3y=0
and then solve the equation to find the domain
o.O there is saying according to which you should keep yourself mum and let others wonder if you know about the thing or not rather than opening it and letting the world know! @KeKiu
domain are those values of y (in this case) for which the function yields a real value..
@shubhamsrg...you lost me
ohhh ok I see
so all your values of y for which the RHS is a real no. are a part of your domain.. clearly, the denominator should NOT be 0 .
See, if denominator becomes 0, then functions become infinite or indetermined.. So this condition must be avoided..
ok understand that
so can someone show me the steps to finding the solution then
Simply put the denominator to 0 and find the values of y.. Note that these values will not be included in the domain..
ok... i will try it out
You can and you will....
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