Find the value of tan (alpha–beta) if cos alpha= –3/5, sin beta= 5/13, 90°

Question

Find the value of tan (alpha–beta) if cos alpha= –3/5, sin beta= 5/13, 90° < alpha < 180°, and 90° < beta < 180°.  ? HELP ANYONE!!!!

tkhunny · Answer

Do you have the formula for $\tan(\alpha - \beta)$?

Note: 3, 4, and 5 constitute a Pythagorean Triple.  $3^{2} + 4^{2} = 5^{2}$

Note: 5, 12, and 13 constitute a Pythagorean Triple.  $5^{2} + 12^{2} = 13^{2}$

anonymous · Answer

Look tan(a-b)=(tana-tanb)/1+tanatanb-----then tana=sina/cosb
                                                                         tanb=sinb/cosb
After substitute the value of tana &tanb  I left the rest for u!!!go Hurry up!!!
a=alpha,b=beta