Does anyone know the how to solve this?

which two equations are equivalent?

A. y=(x +4) to the 2nd power

y= x to the 2nd power + 16

B. y=(x -3) to the 2nd power

y= x to the 2nd power -6x +9

C. y= (x +2) to the 2nd power

y = x to the 2nd power + 2x +2

D. y=(x-6) to the 2nd power

y= x to the 2nd power -12x - 36

Question

Does anyone know the how to solve this?

which two equations are equivalent?

A.    y=(x +4)  to the 2nd power

        y= x to the 2nd power + 16

B.    y=(x -3) to the 2nd power

       y= x to the 2nd power -6x +9

C.   y= (x +2) to the 2nd power

      y = x to the 2nd power + 2x +2

D.  y=(x-6) to the 2nd power

      y= x to the 2nd power -12x - 36

anonymous · Answer

B because x-3)^2
= x^2-6x+9
lol

anonymous · Answer

nincompoop,  Its been a while since i've seen these.. so I dont remember exactly..

anonymous · Answer

how did you get that or how did you came up with that jackson

anonymous · Answer

(X-3)(x-3)
X*X=x^2
-3*x+(-3*x=-6x
-3(-3)=9
x^2-6x+9

anonymous · Answer

and my names rodney

anonymous · Answer

sorry..

anonymous · Answer

okay, Thank you for your help =)

anonymous · Answer

sure