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Mathematics 17 Online
OpenStudy (anonymous):

x^2+3x+15=? HELP?

OpenStudy (raden):

use the quadratic formula,..

OpenStudy (anonymous):

whats that?

OpenStudy (jennychan12):

\[\frac{ -b \pm \sqrt{b^2-4ac}}{ 2a }\]

OpenStudy (hba):

But it is not equal to 0

OpenStudy (anonymous):

ok now what do i do?

OpenStudy (hba):

Do you have to factor it or find x ?

OpenStudy (jennychan12):

x^2+3x+15 a = 1 b = 3 c = 15 plug everything into the quadratic formula. oh and i forgot, it's

OpenStudy (hba):

Actually the standard form of quad equation is \[ax^2+bx+c=0\]so we will not use quad formula.

OpenStudy (jennychan12):

@hba find x using quad. form. sorry. it should be \[x = \frac{ -b \pm \sqrt{b^2-4ac}}{ 2a }\]

OpenStudy (jennychan12):

(i just forgot an x = )

OpenStudy (hba):

There are twp methods to factorize it, 1)Breaking the middle term 2) Completing the square method

OpenStudy (anonymous):

ok thank you so much!

OpenStudy (hba):

@RadEn What do you have to say ?

OpenStudy (hba):

@xxjakkixx You don't have to find x i guess,you have to factorize it.

OpenStudy (jennychan12):

you have to use quadratic formula if it's not factorable. in this case, it's not. so u have to either complete the square or use quadratic formula.

OpenStudy (raden):

hmmm.. i think, xxjakik forgot to give the "zero" at right side

OpenStudy (hba):

@RadEn If their is a zero than you guys are correct,which she has not provided. Else,I am right.

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