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the slope of the line is -2 find the point slope. (4,-6)
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point slope from combines the slope and the point paramaters in the form of y-y(sub1)=m(x-x(sub1))
you have m=-2, y(sub1)=-6 and x(sub1)= 4. these are your paramaters that you will plug into the equation to graph the line
ok.....thts the thing... y-(-6)=-2(x-4) y+6=-2x+8 2x+y-2=0
you dont set it to zero , set it to the form y=mx+b (slope intercept form)
Here,we know tht Slope m=(y-y1)/(x-x1) here m=-2 y1=-6 x1=4
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so...the answer is y - 6 = -2(x+4) ? @ashwinjohn3
You havent got it right... itz y-y1=m(x-x1) here y1=-6 and x1=4 m=-2 y-(-6)= -2(x-4)
Your negatives are off from the equation :)
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