Given: In ∆ABC, segment DE is parallel to segment AC .
Prove: BD over BA equals BE over BC
The two-column proof with missing statements and reasons proves that if a line parallel to one side of a triangle also intersects the other two sides, the line divides the sides proportionally.

Question

Given: In ∆ABC, segment DE is parallel to segment AC .
Prove: BD over BA equals BE over BC 
The two-column proof with missing statements and reasons proves that if a line parallel to one side of a triangle also intersects the other two sides, the line divides the sides proportionally.

anonymous · Answer

attachment

anonymous · Answer

Statement
	
Reason
1. segment DE is parallel to segment AC
	
1. Given
2. Line segment BA is a transversal that intersects two parallel lines
	
2. Conclusion from Statement 1
3. ∡BDE ≅ ∡BAC
	
3. Corresponding Angles Postulate
4.
	
4.
5. ∆ABC ~ ∆DBE
	
5. Angle-Angle (AA) Similarity Postulate
6.
	
6.

anonymous · Answer

I just need 4 and 6 thats all .