Mathematics
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OpenStudy (anonymous):
Which description is true about the expression 12+2a+3(b)-6?
4 terms
1 variable term
1 coefficient
3 constant terms
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OpenStudy (anonymous):
none of them
OpenStudy (anonymous):
4 terms.
OpenStudy (anonymous):
D is probable abswer
OpenStudy (anonymous):
4 terms
OpenStudy (anonymous):
no
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OpenStudy (anonymous):
D is the answer
OpenStudy (anonymous):
there are 2 constants -_-
OpenStudy (anonymous):
12+2a+3-6=2a+3b+6
OpenStudy (anonymous):
No how can it have 3 constants when only 12 -6 = 6 (1 constant)
OpenStudy (anonymous):
there are three constant terms 2,3,6
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OpenStudy (anonymous):
2 and 3 are coefficient of a and b which is constant
OpenStudy (anonymous):
3b is not a constant
OpenStudy (anonymous):
@itsmylife... No, it's not... Any equation has only one constant (the term without a variable)
OpenStudy (anonymous):
and you don't need to modify the expression
OpenStudy (anonymous):
@sparik1997 3 is constant i am not talking about 3b
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OpenStudy (anonymous):
consider it as it is!
OpenStudy (anonymous):
A constant is a term WITHOUT a variable!
OpenStudy (anonymous):
@ayushprasad look if D is not the answer then none of the choices are correct and you need to see constants not variables attached to them
OpenStudy (anonymous):
it has got only 2 variables a and b
OpenStudy (anonymous):
I think 4 terms is right, I will find out once I get it graded. Lol.
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OpenStudy (anonymous):
OMG... those are COEFFECIANTS!!! NOT CONSTANTS!!!
OpenStudy (anonymous):
and 12-6=6 @ayushprasad
OpenStudy (anonymous):
You don't say?
OpenStudy (anonymous):
i know but i am saying in the whole equation there are 3 terms 2a+3b+6 =0 and two variables
OpenStudy (anonymous):
no... there are 2 variables and 2 constants. let's see
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OpenStudy (anonymous):
okay look go with what heart says, make a guess and proceed
OpenStudy (anonymous):
alright
OpenStudy (anonymous):
*not
OpenStudy (anonymous):
Okay, since you are being stubborn, I'll just quit and move on to another question. Bye!
OpenStudy (anonymous):
alright i know you're taking it as coefficient and i am taking it as constant because i see none of the options as correct one
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OpenStudy (anonymous):
see ya
OpenStudy (anonymous):
Btw, who's the one with the medal? This guy :D
OpenStudy (anonymous):
lol i donno
OpenStudy (anonymous):
You mad bro?
OpenStudy (anonymous):
i am ;)
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OpenStudy (anonymous):
:D
OpenStudy (anonymous):
@because100 what was the answer?
OpenStudy (anonymous):
I still have 12 more questions to do before I get the right answer.
OpenStudy (anonymous):
ok, tell us when you are finished
OpenStudy (anonymous):
Will do.
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OpenStudy (anonymous):
4 terms was correct.
OpenStudy (anonymous):
:D
OpenStudy (anonymous):
Lol ^_^ Thanks for answering.
OpenStudy (anonymous):
;)