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Find the absolute max and min values of func f(x)=xlnx in the interval [1,e^2] i am waiting for your helping
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First you need to find the critical points. A critical point is when \(f'(x) = 0\).
and then?
Find f'(x) first, set it equal to zero, then solve for x...replace the value you have to the original equation to determine which value is max and which value is min
got it thank u for solution
A critical point is also anywhere that the function is not defined. When you find the critical point, you plug in the x coordinate into the original function.
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you mean like f'(x)=1/x x=0 ?
I mean anywhere the derivative isn't defined is a critical point.
Yes.
yes it makes sense :) thank u
Great work all, awesome :)
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