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simplify the following radical. ...
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\[\sqrt{18x ^{13}}\]
hint : 18 = 2*9 \(x^{13}=x.x^{12}\)
\[3^{x6\sqrt{2x }}\]
is the answer...
if you meant \(3x^6\sqrt{2x}\) then its correct.
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u know how ?
nope.. lol. not at all actually
thats what i meant... :)
u know that \(\sqrt a^2=a \) ?
so whatever a squared is, would still just be the base?
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\[\sqrt{12^{2}} would =12?\]
im horrible at this.. lol. sorry
\(\large \sqrt{18x ^{13}} = \sqrt{(2*3^2)(x^1.x^{12})}\) did u get that ^ ?
ok.. step by step... (2x3)= \[6^{2}\] ?
\(\large 18=2*9=2*3^2\) ok ?
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ooohh, ok, got it...
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