Question

Find all zeros 5x^5-20x^4-40x^3-16x^2-45x+180=0

Answer 1

@zepp

Answer 2

What do you mean by "Find all zeros" ?

Answer 3

find the zeros of th eq

Answer 4

Use rational root theorem to find first zero. Then use synthetic division to factor it out.

Answer 5

hi @evy15 are you in numerical analysis?
the root are -2.07316, 1.2355, 5.5573 and two complex roots
check it for yourself if they are true

Answer 6

@evy
though the equation is 5x^5-20x^4-40x^3-16x^2-45x+180=0 correct
bu t may be i feel u have typed in -16X^2 instead of 160x^2

Answer 7

no its correct

Answer 8

can someone please help me and explain to me how to begin this problem

Answer 9

can someone respond

Answer 10

Have you done numerical methods in your course?
This is not a problem that can be solved by factorization, or rearrangements.
I suggest you triple check the question.

Answer 11

its correct can you tell me how to begin

Answer 12

It can be solved numerically, or graphically. Are these expected methods to use in your course?

Answer 13

yes the thing is i missed a day in class and now i dont know how to work this out

Answer 14

Are you working on factorization, Descartes rule of signs, etc.?
I suggest you check your course outline to see what you're expected to know, or check with a friend to see what has been done that day. The prof would also be pleased to tell you what has been covered that day.
This problem requires numerical methods which are techniques completely different from your previous problems.

Answer 15

can u help me and explain it to me

Answer 16

i have tried to use the book but i keep getting it wrong

Answer 17

What is the name of your math course?

Answer 18

Algebra 2

Answer 19

Then there is probably another typo in the question.

Answer 20

there isn't, i already checked

Answer 21

I believe you, but your prof made a typo!
Check in the index of your textbook to see if Newton's method is in there.
What is the title of your textbook?

Answer 22

ok

Answer 23

Im not sure, hold on

Answer 24

Holt McDougal Larson Algebra 2

Answer 25

Can you find "Newton's method" in the index?

Answer 26

On which chapter are you working?

Answer 27

Is it paper home-work or online?

Answer 28

its a take home test and i couldnt find it

Answer 29

As matricked pointed out, IF -16x^2 had been +160x^2, then there are rational roots obtainable by grouping.
5x^5-20x^4-40x^3+160x^2-45x+180
=5(x^5-4x^4-8x^3+32x^2-9x+36)
\(= 5( x^4(x-4) -8x^2(x-4) -9(x-4)) \)
\(= 5(x-4)(x^4-8x^2-9) \)
\(= 5(x-4)(x^2-9)(x^2+1) \)
\(= 5(x-4)(x+3)(x-3)(x^+1) \)

Answer 30

*last factor is \( (x^2+1) \)

Answer 31

ok do you solve for them now

Answer 32

hold on a second, im sorry