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uhmmm ya i dk how to do these still d(-2)= -3/2(-2)+5
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I think you already figured it out. It looks like you plugged in (-2) for whatever variable you are given in d(x) or d(t) etc.,//
ya uhm i need the answer i know i plugged in the -2 but thats not what i was looking for
Multiply and add.
d(-2)= -3/2(-2)+5 d(-2)= (-3/2)(-2/1)+5 ... rewrite -2 as -2/1 d(-2)= (-3*(-2))/(2*1)+5 ... multiply straight across d(-2)= 6/2+5 ... multiply I'll let you finish. Remember to follow PEMDAS
17?
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how are you getting that?
How did you get 17?
idkkkkkk omggggod
\[\frac{-3}{2}(-2)+5\]
The (-2) and (2) cancel out to give you (-1). (-3)(-1) + 5 = ??
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