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i need to solve \[\cos \left( \frac{ \pi }{ 6 }+x \right)-\cos \left( \frac{ \pi }{ 6 }-x \right)=1\]
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Might help to use some trig identities. Give me a second.
\[ \cos(x+y) = \cos(x)\cos(y) - \sin(x)\sin(y) \\ \]
In which case you would treat \(x = \pi / 6\) and \(y = x\), etc.
Forgive me for reusing that \(x\) variable.
lol You are forgiven :)
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cos(x-y)=Cos(x)Cos(y)+Sin(x)Sin(y)
thanks. i got it
What was your answer for x?
\[\frac{ 3\pi }{ 2 }\]
Ya got that too :)
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good. yeah!
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