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Find the indefinite integral of inverse secant.
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I believe there is a formula for this integral? but you can use integration by parts to solve.
HINT: u = arcsec(x) and dv = 1
u mean find \[ \int\text{arcsec }x\,dx \]
i agree with abb0t. use integration by parts.
Also, in case you didn't know: \[\sec^{-1}(x) = arcsec(x)\]
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u mean \[ \large u=\text{arcsec }x\qquad dv=dx \]
I don't like to include the dx in my work cuz it sometimes confuses me when I'm doing things quickly..
ok, I've done integration by parts but I got stuck again here. |dw:1356923510125:dw| what will happen to the 1/2x at the front?
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